Question

(3+3 2в корне) (1-2 2в корне)

Answer 1

= 3-3*2V2+3V2-3V2*2V3=3-6V2+3V2-12=-9-3V3

Answer 2

Объяснение:

$(3+3\sqrt2)(1-2\sqrt2)=3-6\sqrt2+3\sqrt2-6\cdot 2=3-3\sqrt2-12=-9-3\sqrt2=\\\\\\=-3\, (3+\sqrt2)$