Question

Допоможіть, знайти значеня виразу. пжжпжп​

Answer 1

Ответ:

Объяснение:

$=\frac{(x-y)(x+y)}{2x^{2} y^{2} } *\frac{20xy^{2} }{x-y} =\frac{x+y}{x} *10=\frac{10(x+y)}{x} =\frac{10x+10y}{x}$

$\frac{10+10*8}{\frac{3}{\frac{1}{3} } } =\frac{10+80}{\frac{3}{\frac{1}{3} } } =\frac{30}{\frac{1}{3} } =90$

Answer 2

$\dfrac{x^{2} -y^{2} }{2x^{2} y^{2} } :\dfrac{x-y}{20xy^{2} } =\dfrac{(x-y)(x+y)}{2x^{2} y^{2} } \cdot\dfrac{20xy^{2} }{x-y} =\boxed{\dfrac{10(x+y)}{x} }\\\\\\x=\dfrac{1}{3} \ ; \ y=2\dfrac{2}{3} =\dfrac{8}{3} \\\\\\\boxed{\dfrac{10(x+y)}{x} }=\dfrac{10\cdot (\frac{1}{3} +\frac{8}{3} )}{\frac{1}{3} }=10\cdot 3\cdot 3=\boxed{90}$