Question

Пожалуйста помогите!!!
у²-8у/у-3 - 9+2у/3-у​

Answer 1

Ответ:

y-3

Пошаговое объяснение:

$\frac{y^{2}-8y }{y-3}-\frac{9+2y}{3-y} = \frac{y^{2}-8y }{y-3}-\frac{9+2y}{-1*(y-3)}=\frac{y^{2}-8y }{y-3}-\frac{-1*(9+2y)}{y-3} = \frac{y^{2}-8y-(-9-2y) }{y-3} = \frac{y^{2}-8y+9+2y }{y-3}= \frac{y^{2} -6y+9}{y-3}$

$y^{2} -6y+9 = a(y-y_{1} )(y-y_{2} )$

По т. Виета:

$y_{1} +y_{2} = 6$

$y_{1} *y_{2} = 9$

$y_{1} = y_{2} = 3$

$y^{2} -6y+9 = a(y-y_{1} )(y-y_{2} )$ = $(y-3)^{2}$

$\frac{y^{2} -6y+9}{y-3}$ = $\frac{(y-3)^{2} }{y-3}$ = y-3