Question

СРОООООЧНО 50 БАЛОВ!!!!!!!!!!!!!!!

Answer 1

Ответ:

Объяснение:

$=\frac{(c-3)^{2} }{c-8} *\frac{64*c^{2} }{c-3} =\frac{(c-3)^{2} }{c-8} *\frac{(8-c)(8+c)}{c-3} =\frac{(c-3)^{2} }{c-8} *\frac{-(8-c)(8+c)}{c-3} = (c-3)(-(8+c))=-(8c+c^{2} -24-3c)=-5c-c^{2} +24=-c^{2} -5c+24 \\-(-2\frac{1}{5} )^{2} -5(-2\frac{1}{5})+24= -(-2\frac{1}{5) } )^{2} -5*(\frac{11}{5} )+24=-(-2\frac{1}{5} )^{2} +11+24=-(-\frac{11}{5} )^{2} +35=-\frac{121}{25} +35=\frac{754}{25} =30\frac{4}{25}$

Answer 2

$\frac{c^2-6c+9}{c-8} :\frac{c-3}{64-c^2} =$

$=\frac{9-6c+c^2}{c-8} *\frac{64-c^2}{c-3} =$

$=\frac{(3-c)^2}{8-c} *\frac{64-c^2}{3-c} =$

$=\frac{(3-c)(3-c)}{8-c} *\frac{(8-c)(8+c)}{3-c} =$

$=\frac{(3-c)}{1} *\frac{(8+c)}{1} =$

$=(3-c)(8+c)=$

$=-(c-3)(8+c)$

Ответ:     $-(c-3)(8+c)$

При  $c=-2\frac{1}{5} =-2,2$

$-(-2,2-3)(8-2,2)=-(-5,2)(5,8)=30,16$