Предмет: Алгебра, автор: pilipenkozenicka

не удаляйте пж.Помогите срочно есть 30 минут до здачи домашнего задания​

Приложения:

Ответы

Автор ответа: nurayrahmetilada2012
0
1.=ab-3a+2b-2•3=ab-3a+2b-6
2.=m•m+5m-4m-4•5=m^2+5m-4m-20=m^2+m-20
3.3x•2x+3x•5-2x-5=6x^2+15x-2x-5=6x^2+13x-5
Автор ответа: lshykov321
0

Объяснение:

1.

(a + 2)(b - 3) = ab - 3a + 2b - 6

2.

(m - 4)(m + 5) = m \times m + 5m - 4m - 4 \times 5 = m {}^{2}  + m - 20

3.

(3x - 1)(2x + 5) = 3x \times 2x + 3x \times 5 - 2x - 5 = 6x {}^{2} + 13x - 5

4.

(3b {}^{2}  + 2)(2b - 4) = 3b {}^{2}  \times 2b - 3b {}^{2}  \times 4 + 2 \times 2b - 2 \times 4 = 6b {}^{3}  - 12b {}^{2}  + 4b - 8

5.

(4x - y)(2x - 3y) = 4x \times 2x - 4x \times 3y - 2xy - y \times ( - 3y) = 8x {}^{2}  - 12xy - 2xy + 3y {}^{2}  = 8x {}^{2}  - 14xy + 3y {}^{2}

6.

(3a {}^{2}  + a)(5a {}^{2}  - 2a) = 3a {}^{2}  \times 5a {}^{2}  - 3a {}^{2}  \times 2a + a \times 5a {}^{2}  - a \times 2a = 15a {}^{4}  - 6a {}^{3}  + 5a {}^{3}  - 2a {}^{2}  = 15a {}^{4}  - a {}^{3}  - 2a {}^{2}

7.

( - x - 2)(2x {}^{3}  - 3) =  - x \times 2x {  }^{3}  - x \times ( - 3) - 2 \times 2x {}^{3}  - 2 \times ( - 3) =  - 2x {}^{4}  + 3x - 4x {}^{3}  + 6

8.

(3a {}^{2}  - 5b)(5a {}^{2}  + b) = 3a {}^{2}  \times 5a {}^{2}  + 3a {}^{2} b - 5b \times  5a {}^{2}  - 5b \times b = 15a {}^{4}  + 3a {}^{2} b - 25a {}^{2} b - 5b {}^{2}  = 15a {}^{4}  - 22a {}^{2} b - 5b {}^{2}

9.

(y + 3)(y {}^{2}  - 2y + 5) = y \times (y {}^{2}  - 2y + 5) + 3(y {}^{2}  - 2y + 5) = y {}^{3}  - 2y {}^{2}  + 5y + 3y {}^{2}  - 6y + 15 = y {}^{3}  + y {}^{2}  - y + 15

10.

(m + 3n)(m {}^{2}  - 6mn - n {}^{2} ) = m \times (m {}^{2}  - 6mn - n {}^{2} ) + 3n \times (m {}^{2}  - 6mn - n {}^{2} ) = m {}^{3}  - 6m {}^{2} n - mn {}^{2}  + 3m {}^{2} n - 18mn {}^{2}  - 3n {}^{3}  = m {}^{3}  - 3m {}^{2} n - 19mn {}^{2}  - 3n {}^{3}

11.

2x \times (3x - 1)(2x + 5) = (6x {}^{2}  - 2x)(2x + 5) = 12x {}^{3}  + 30x {}^{2}  - 4x {}^{2}  - 10x = 12x {}^{3}  + 26x {}^{2}  - 10x

12.

 - 3x {}^{2}  \times (2 - 3x)(3x {}^{2}  + 11x) = ( - 6x {}^{2}  + 9x {}^{3} )(3x {}^{2}  + 11x) =  - 18x {}^{4}  - 66x {}^{3}  + 27x {}^{5}  + 99x {}^{4}  = 81x {}^{4}  - 66x {}^{3}  + 27x {}^{5}  = 27x {}^{5}  + 81x {}^{4}  - 66x {}^{3}

Похожие вопросы