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Answer 1

$\frac{xy+y^2}{8x}:\frac{x+y}{2x}=\frac{y(x+y)*2x}{8x*(x+y)}=\frac{y}{8}\\\\\\6x^2y*\frac{2x}{3y^2}=\frac{6x^2y*2x}{3y^2}=\frac{4x^3}{y}\\\\\\b-\frac{2a}{a-b}*\frac{a^2-b^2}{4a}=b-\frac{2a(a-b)(a+b)}{(a-b)*4a}=b-\frac{a+b}{2}=\frac{2b-(a+b)}{2}=\\\\=\frac{2b-a-b}{2}=\frac{b-a}{2}$