Question

(- 1/2 * x ^ 4 * y) ^ 4 * (16x ^ 4 * y ^ 3) ^ 2
поможіть​

Answer 1

Ответ:

$\displaystyle \Big(-\frac{1}{2}\, x^4y\Big)^4\cdot \Big(16\, x^4y^3\Big)^2=\frac{1}{16}\, x^{16}y^4\cdot 16^2\, x^8y^6=16\, x^{24}\, y^{10}$