Question

$- 2x {}^{2} + 10x - 8 \leqslant 0$
Помогите пожалуйста
​

Answer 1

Ответ:

$2x - 10x + 8 = 0 \\ 10 ^{2} - 4 \times 2 \times 8 = 100 - 64 = 36 \\ x1 = \frac{10 - 6}{2 \times 2} = \frac{4}{4} = 1 \\ x2 = \frac{10 + 6}{2 \times 2} = \frac{16}{4} = 4$