Предмет: Физика, автор: KURAM351

Дан график движения двух тел. Известно, что оба тела движутся равномерно и прямолинейно.
Вычисли скорость каждого тела и сравни скорости движения тел.
Какой путь пройдут эти тела за 3 мин.

Ответ: (округли до десятых!)

скорость I тела —
м/с,

скорость II тела —
м/с,

скорость I тела
, чем скорость II тела (в окошко напиши знак '<' или '>'),

путь I тела за 3 мин. —
м,

путь II тела за 3 мин. —
м.

Приложения:

Ответы

Автор ответа: kuklintima03
6

Ответ:

1)

S=v0t+at^2 ÷2

Формула при равномерном движении

S=v0t+0

V=s÷t

V1=40м÷20с=2м/с

V2=160м÷120с=1. (3) м/с

2)

V1>V2

|2м/с|>|1.(3)м/с|

3)

S1=VT

S1=180с×2м/с=360

S2=180c×160м÷120с=240м

Объяснение:

Автор ответа: DedStar
19

Ответ:

Объяснение:

Скорость первого тела:

V₁ = 120 / 20 = 6 м/с

Скорость второго тела:

V₂ = 80/80 = 1 м/с

Скорость первого тела больше скорости второго тела в 6 раз:

V₁ > V₂

Время:

t = 3 мин = 180 c

Путь первого тела:

S₁ = V₁·t = 6·180 = 1 080 м

Путь второго тела:

S₂ = V₂·t = 1·180 = 180 м

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