Question

(a⁵)6 • (a⁴b²)⁷: (a²⁹b⁷)2;​

Answer 1

$(a^5)^{6} *(a^4b^2)^{7} :(a^{29} b^7)^{2}=$

$=a^{30} *a^{28} b^{14} :a^{58} b^{14} =$

$= a^{30+28-58} b^{14-14}=$

$=a^0b^0=1*1=1$