Question

решить
3x²-8y²/x²-2xy - 3xy-x²/xy-2y²

Answer 1

Объяснение:

$\frac{3x {}^{2} - 8y {}^{2} }{x {}^{2} - 2xy} - \frac{3xy - x {}^{2} }{xy - 2y {}^{2} } = \frac{3x {}^{2} - 8y {}^{2} }{x \times (x - 2y)} - \frac{3xy - x {}^{2} }{y \times (x - 2y)} = \frac{y \times (3x {}^{2} - 8y {}^{2} ) - x \times (3xy - x {}^{2} )}{xy \times (x - 2y)} = \frac{3x {}^{2} y - 8y {}^{3} - 3x {}^{2}y + x {}^{3} }{x {}^{2}y - 2xy {}^{2} } = \frac{ - 8y {}^{3} + x {}^{3} }{x {}^{2}y - 2xy {}^{2} }$