Question

ЦДЗ.укажите правильный ответ

Answer 1

${x}^{2} {(x + 7)}^{3} {(x + 5)}^{4} < 0$

${x}^{2} {(x + 7)}^{3} {(x + 5)}^{4} = 0$

${x}^{2} = 0$

$x_1 = 0$,

${(x + 7)}^{3} = 0$

$x + 7 = 0$

$x_2 = - 7$,

${(x + 5)}^{4} = 0$

$x + 5 = 0$

$x_3 = - 5$.

Ответ: $x \in(- \infty ; - 7)$