Question

алё? решите пожалуйста ​

Answer 1

$\frac{14x^{2}-y}{7x}-2x=\frac{14x^{2}-y}{7x} -\frac{14x^{2}}{7x} =\frac{14x^{2}-y-14x^{2}}{7x} =\frac{-y}{7x} =\frac{-(-14)}{7*0,5} =\frac{14}{7*0,5} =\frac{2}{0,5} =4$

Answer 2

Ответ:

$x=0,5\ \ ,\ \ y=-14\\\\\\\dfrac{14x^2-y}{7x}-2x=\dfrac{14x^2-y-2x\cdot 7x}{7x}=\dfrac{14x^2-y-14x^2}{7x}=\dfrac{-y}{7x}=\dfrac{14}{7\cdot 0,5}=\\\\\\=\dfrac{2}{1/2}=\dfrac{2\cdot 2}{1}=4$