Question

Решить пожалуйста мне это

Answer 1

Ответ:

Пошаговое объяснение:

1.

1) $\frac{4a}{7b} = \frac{4a+7b}{ab}$

2)$\frac{9}{m} -\frac{5}{mn} =\frac{9n-5}{mn}$

3) $\frac{4}{12xy} -\frac{11}{18xy} =\frac{1}{3xy} -\frac{11}{18xy} = -\frac{5}{18xy}$

4)$= \frac{10ab*5m}{10ab*3ab} +\frac{6b*2n}{6b*5a^{2}b } -\frac{15a*7p}{15a*2ab^{2} } =\frac{50abm}{30a^{2} b^{2} } +\frac{12bn}{30a^{2} b^{2} } -\frac{105ap}{30a^{2} b^{2} } =\frac{50abm+12bn-105ap}{30a^{2} b^{2} }$

5) $=\frac{b(3a-4b)+8a^{2} +4b^{2} }{ab} =\frac{3ab-4b^{2}+8a^{2} +4b^{2} }{ab} =\frac{a(3b+8a)}{ab} = \frac{3b+8a}{b}$

6) $=\frac{3c^{2} -2c+4-c(2c-9)}{bc^{2} } =\frac{3c^{2}-2c+4-2c^{2} +9c }{bc^{2} }=\frac{c^{2}+7c+4 }{bc^{2} }$

2.

1) $=\frac{x-3}{3(x+2)} -\frac{x-6}{x+2} =\frac{x-3-3(x-6)}{3(x+2)} = \frac{x-3-3x+18}{3x+6} =\frac{-2x+15}{3x+6}$

2)  $=\frac{x+4}{5(x-2)} +\frac{3-x}{4(x-2)} =\frac{4(x+4)+5(3-x)}{20(x-2)} =\frac{4x+16+15-5x}{20x-40} =\frac{-x+31}{20x-40}$

3)

$=\frac{(y+6)^{2}-(y-6)*(y+2) }{(y-6)*(y+6)} =\frac{y^{2}+12y+36-(y^{2} +2y-6y-12) }{y^{2} -36} =\frac{y^{2} +12y+36-(y^{2} -4y-12)}{y^{2}-36 } =\frac{y^{2}+12y+36-y^{2} +4y+12 }{y^{2}-36 } =\frac{16y+48}{y^{2} -36}$

4)

$=\frac{3x}{4(x-1)} +\frac{5x}{-7(x-1)} =\frac{3x}{4(x-1)} +\frac{5x}{-7(x-1)} =\frac{3x}{4(x-1)} -\frac{5x}{7(x-1)} =\frac{x}{28(x-1)} =\frac{x}{28x-28}$

5)

$=\frac{2b}{2b+c} -\frac{4b}{(2b+c)^{2} } =\frac{2b(2b+c)-4b}{(2b+c)^{2} } =\frac{4b^{2}+26c-4b }{2b+c^{2} }$

6)

$=\frac{2}{(a-3)(a+3)} -\frac{1}{a(a+3)} =\frac{2a-(a-3)}{a(a-3)(a+3)} =\frac{2a-a+3}{a(a-3)(a+3)} =\frac{1}{a(a-3)} =\frac{1}{a^{2} -3a}$