Question

Обчисліть tg 45-cos 60= √ 2• sin 45+√ 3 cos 30

Answer 1

$\bf1) \tg45 {}^{ \circ} - \cos60 {}^{ \circ} = 1 - 0.5 = 0.5. \\ \bf2) \sqrt{2} \sin45 {}^{ \circ} + \sqrt{3} \cos30 {}^{ \circ} = \sqrt{2} \cdot \dfrac{ \sqrt{2} }{2} + \sqrt{3} \cdot \dfrac{ \sqrt{3} }{2} = \dfrac{2}{2} + \dfrac{3}{2} = 1 + 1.5 = 2.5.$