Question

Решите уровнение
3(4х+2)=7(2-8х)-10

Answer 1

$3*(4x+2)=7*(2-8x)-10$

$12x+6=14-56x-10$

$12x+56x=-6+14-10$

$68x=-2$

$x=-2:68$

$x=-\frac{1}{34}$

Проверка

$3*(4*(-\frac{1}{34})+2)=7*(2-8*(-\frac{1}{34} ))-10$

$3*(-\frac{4}{34}+2)=7*(2+\frac{8}{34} )-10$

$3*\frac{64}{34}=7*\frac{76}{34} -10$

$\frac{192}{34}=\frac{532}{34} -\frac{340}{34}$

$\frac{192}{34}=\frac{192}{34}$

Ответ:  $-\frac{1}{34}$