Question

186. Решите уравнение: ​

Answer 1

$\displaystyle a) \ \sqrt{(x+4)^2} =25 \ \ \ \ B) \ \sqrt{(7-x)^2}=0 \\\\|x+4|=5 \qquad \qquad \qquad \ \ \ |7-x|=0 \\\\ x_1=1 \ \ ; \ \ x_2=-9 \qquad \qquad x=7 \\\\\\b) \ \sqrt{(x-3)^2} =16 \qquad \Gamma ) \ \sqrt{(9+x)^2}=-4 \\\\ |x-3|=4 \ \ \ \ \ \ \ \ \qquad \ \ \ \ \ \ (9+x)^2<0 \to \o \\\\x_1=7 \ \ ; \ x_2=-1$