Question

помогите пожалуйста ​

Answer 1

Ответ:

$\sqrt[3]{-125}+\dfrac{1}{8}\sqrt[6]{64}=\sqrt[3]{-5^3}+\dfrac{1}{8}\sqrt[6]{2^6}=-5+\dfrac{2}{8}=-5+\dfrac{1}{4}=-4\dfrac{3}{4}\\\\\\\sqrt[5]{32}-0,5\sqrt[3]{-216}=\sqrt[5]{2^5}-0,5\sqrt[3]{-6^3}=2-0,5\cdot (-6)=2+3=5\\\\\\-\dfrac{1}{3}\sqrt[4]{81}+\sqrt[4]{625}=-\dfrac{1}{3}\sqrt[4]{3^4}+\sqrt[4]{5^4}=-\dfrac{1}{3}\cdot 3+5=-1+5=4$

$\sqrt[3]{-1000}-\dfrac{1}{4}\sqrt[4]{256}=\sqrt[3]{-10^3}-\dfrac{1}{4}\sqrt[4]{4^4}=-10-\dfrac{1}{4}\cdot 4=-10-1=-11\\\\\\\sqrt[5]{\dfrac{1}{243}}+\sqrt[3]{-0,001}-\sqrt[4]{0,0016}=\sqrt[5]{\dfrac{1}{3^5}}+\sqrt[3]{-0,1^3}-\sqrt[4]{0,2^4}=\dfrac{1}{3}-0,1-0,2=\\\\=\dfrac{1}{3}-0,3=\dfrac{1}{3}-\dfrac{3}{10}=\dfrac{10-9}{30}=\dfrac{1}{30}$