Question

$(3x-2)(4+\frac{1}{3} x)=0$
$(2x+1.2)(x+1)(0.7x+0.21)=0$
$\frac{2x}{7} +\frac{x}{4} =\frac{15}{14}$
$-\frac{x}{8} +1=\frac{x}{12}$

Answer 1

Ответ:

1) 2x + 1.2 = 0;

2x = -1.2;

x = -1.2 : 2;

x = -0.6;

2) x + 1 = 0;

x = -1;

3) 0.7x - 0.21 = 0;

0.7x = 0.21;

x = 0.21 : 0.7;

x = 0.3.

Ответ: x = -0.6; x = -1; x = 0.3 корни уравнения.