Question

Задание на скрине....​

Answer 1

$\sin \alpha = \sqrt{1 - \cos {}^{2} \alpha } \to \sin \alpha = \sqrt{1 - 0.5 {}^{2} } \to \sin \alpha = \sqrt{0.75} \to \sin \alpha = \dfrac{ \sqrt{3} }{2} . \\ \\ \\ \tg \alpha = \dfrac{ \sin \alpha }{ \cos \alpha } = \dfrac{ \dfrac{1}{2} }{ \dfrac{ \sqrt{3} }{2} } = \dfrac{1}{ \sqrt{3} } = \dfrac{ \sqrt{3} }{3} .$