Question

Хелп плиз гайс . Упростите:

Answer 1

Ответ:

$\dfrac{(a-b)^{2}}{a-b+1}$

Объяснение:

$\bigg (a+\dfrac{a-b}{a+b}-b \bigg ): \bigg (\dfrac{2a+1}{a^{2}-b^{2}}+1 \bigg )= \bigg (a-b+\dfrac{a-b}{a+b} \bigg ): \dfrac{2a+1+a^{2}-b^{2}}{a^{2}-b^{2}}=$

$=\dfrac{(a-b)(a+b)+a-b}{a+b}:\dfrac{a^{2}+2a+1-b^{2}}{a^{2}-b^{2}}=\dfrac{(a-b)(a+b+1)}{a+b}:\dfrac{(a+1)^{2}-b^{2}}{a^{2}-b^{2}}=$

$=\dfrac{(a-b)(a+b+1)}{a+b}:\dfrac{(a+1-b)(a+1+b)}{(a-b)(a+b)}=\dfrac{(a-b)(a+b+1)}{a+b} \cdot$

$\cdot \dfrac{(a-b)(a+b)}{(a-b+1)(a+b+1)}=\dfrac{(a-b)(a+b+1)(a-b)(a+b)}{(a+b)(a-b+1)(a+b+1)}=\dfrac{(a-b)(a-b)}{a-b+1}=$

$=\dfrac{(a-b)^{2}}{a-b+1};$