Question

помогите срочно пожалуйста

Answer 1

$y=\sqrt{4x+9}-\dfrac{3}{\sqrt{11-2x}} \\\\\\\displaystyle\left \{ {{4x+9\geq 0 } \atop {11-2x>0}} \right. \\\\\\\displaystyle\left \{ {{4x\geq -9} \atop {-2x>-11}} \right. \\\\\\\displaystyle\left \{ {{x\geq -2,25} \atop {x<5,5}} \right. \\\\\\Otvet:\boxed{x\in\Big[-2,25 \ ; \ 5,5\Big)}$