Question

помогите пожалуйста с алгеброй!!

Answer 1

$1) \ \dfrac{y-x}{y^{2} -9}-\dfrac{x-3}{9-y^{2} } = \dfrac{y-x}{y^{2} -9}+\dfrac{x-3}{y^{2}-9 } =\dfrac{y-x+x-3}{y^{2}-9 } =\\\\\\=\dfrac{y-3}{(y-3)(y+3)}=\boxed{\dfrac{1}{y+3}}$

$2) \ \dfrac{4x}{x+1} -\dfrac{x-3}{x+1} =\dfrac{4x-x+3}{x+1}=\dfrac{3x+3}{x+1}=\dfrac{3(x+1)}{x+1}=\boxed3$

Answer 2

2) 3х + 3 / х + 1 =
3(х + 1) / х + 1 = 3