Question

Решите пожалуйста 5 и 6 задание!!!

Answer 1

$\displaystyle5.\\1)\frac{x}{4} -\frac{2x-1}{6} +\frac{x-5}{2} \leq 0\\\\3x-2(2x-1)+6(x-5)\leq 0\\3x-4x+2+6x-30 \leq 0\\5x-28\leq 0\\5x\leq 28\\\\x\leq \frac{28}{5} \\\\x\in(-\infty;\frac{28}{5} ]\\\\2) 6x+5<2(x-7)+4x\\6x+5<2x-14+4x\\0x<-9\\x\in\varnothing$

$\displaystyle 6.\\\\\left \{ {{(x+1)^2-x(x-1)\leq 5+x} \atop {4x+3>x-4}} \right. \\\\\left \{ {{x^2+2x+1-x^2+x\leq 5+x} \atop {3x>-7}} \right. \\\\\left \{ {{2x\leq 4} \atop {3x>-7}} \right.\\\\\left \{ {{x\leq 2} \atop {x>-\dfrac{7}{3} }} \right.\\\\x\in(-\frac{7}{3}; 2]$