Question

Помогите решить номера:161, 126(4,5)

Answer 1

Ответ:

Пошаговое объяснение:

№ 161

$1\frac{1}{3} \\\\ 4\frac{1}{2} \\\\ 2\frac{2}{7} \\\\2\frac{4}{5} \\\\5\frac{5}{6} \\\\6\frac{4}{5} \\\\10\frac{1}{4}$

16 целых 5/9

18 целых 2/13

14 целых 24/35

13 целых 8/15

№126

4)    $\frac{3}{5} и \frac{3}{5}$

5) выходит с остатком

Answer 2

№ 161

$\displaystyle\\\frac{4}{3}=1\frac{1}{3} \\\\\\\frac{9}{2}=4\frac{1}{2}\\\\\\\frac{16}{7}=2\frac{2}{7}\\\\\\\frac{14}{5}=2\frac{4}{5}\\\\\\\frac{35}{6}=5\frac{5}{6}\\\\\\\frac{68}{10}=6\frac{8}{10}=6\frac{4}{5} \\\\\\\frac{123}{12}=10\frac{3}{12}=10\frac{1}{4}\\\\\\\frac{149}{9}= 16\frac{5}{9}\\\\\\\frac{236}{13}=18\frac{2}{13}\\\\\\\frac{514}{35}=14 \frac{24}{35}\\\\\\\frac{812}{60}=13\frac{32}{60}=13\frac{8}{15}$

№ 126

$\displaystyle\\1)\frac{6}{8}=\frac{15}{20}\\\\\\\frac{6*5}{8*5}=\frac{15*2}{20*2}\\\\\\\frac{30}{40}=\frac{30}{40}\\\\\\2)\frac{10}{15} >\frac{6}{18}\\\\\\\frac{10*6}{15*6} >\frac{6*5}{18*5}\\\\\\\frac{60}{90} >\frac{30}{90}\\\\\\3)\frac{17}{42} <\frac{13}{28}\\\\\\\frac{17*2}{42*2}<\frac{13*3}{28*3}\\\\\\\frac{34}{84}<\frac{39}{84}\\\\\\4)\frac{18}{30}=\frac{21}{35}\\\\\\\frac{18*7}{30*7}=\frac{21*6}{35*6}\\\\\\\frac{126}{210} =\frac{126}{210}$

$\displaystyle\\5)\frac{25}{36} <\frac{19}{24}\\\\\\\frac{25*2}{36*2}<\frac{19*3}{24*3}\\\\\\\frac{50}{72}<\frac{57}{72}$