Question

помогите пожалуйста ​

Answer 1

Ответ:

1)

$\frac{6y - 3}{5y} - \frac{y + 2}{5y} = \frac{6y - 3 - y - 2}{5y} = \frac{5y - 5}{5y} = \frac{5(y - 1)}{5y} = \frac{y - 1}{y}$

2)

$\frac{10p}{p - q} + \frac{3p}{q - p} = \frac{10p}{p - q} - \frac{3p}{p - q} = \frac{10p - 3p}{p - q} = \frac{7p}{p - q}$

3) а)

$\frac{c}{4} - \frac{d}{12} = \frac{3c - d}{12}$

б)

$\frac{3}{2x} - \frac{2}{3x} = \frac{3 \times 3 - 2 \times 2}{6x} = \frac{9 - 4}{6x} = \frac{5}{6x}$