Question

помогите решить 9 задание

Answer 1

Ответ:

9)

$\frac{5 + 0.8x}{ {x}^{2} + 5x } + \frac{1}{5x + 25} = \frac{5 + 0.8x}{x( x+ 5)} + \frac{1}{5(x + 5)} = \frac{5(5 + 0.8x) + x}{5x(x + 5)} = \frac{25 + 4x + x}{5x(x + 5)} = \frac{25 + 5x}{5x(x + 5)} = \frac{5(5 + x)}{5x(x + 5)} = \frac{1}{x}$

Если х=0,01, то

$\frac{1}{x} = \frac{1}{0.01} = \frac{1}{ \frac{1}{100} } = \frac{1 \times 100}{1} = 100$