Question

помогите пожалуйста ❤​

Answer 1

Ответ:на фото

Объяснение:

Answer 2

Объяснение:

1.

$a)\ \frac{18d^3e}{24d^3e^3} =\frac{3}{4e^2};\\b)\ \frac{ut+t^2}{t^5}=\frac{t*(u+t)}{t^5} =\frac{u+t}{t64};\\c)\ \frac{d+6c}{d^2-36c^2} =\frac{d+6c}{(d+6c)*(d-6c)}=\frac{1}{d-6c}.$

2.

$a)\ \frac{f+g}{f-g} +\frac{f}{g} =\frac{g*(f+g)+f*(f-g)}{g*(f-g)}=\frac{fg+g^2+f^2-fg}{g*(f-g)} =\frac{f^2+g^2}{g*(f-g)} .\\b)\ \frac{6g^2}{g^2-36}-\frac{6g}{g+6} = \frac{6g^2}{(g+6)*(g-6)}-\frac{6g}{g+6} =\frac{6g^2-6g*(g-6)}{(g+6)*(g-6)}=\frac{6g^2-6g^2+36g}{g^2-36} =\frac{36g}{g^2-36}.\\c)\ \frac{6v^2}{v-4} -6v=\frac{6v^2-6v*(v-4)}{v-4}=\frac{6v^2-6v^2+24v}{v-4}=\frac{24v}{v-4} .$

3.

$\frac{12}{d-7} -\frac{7d}{(d-7)^2} -\frac{5d}{d^2-49}= \frac{12}{d-7} -\frac{7d}{(d-7)^2} -\frac{5d}{(d-7)*(d+7)}=\frac{12*(d-7)*(d+7)-7d*(d+7)-5d*(d-7)}{(d-7)^2*(d+7)}=\\=\frac{12*(d^2-49)-7d^2-49d-5d^2+35d}{(d-7)^2*(d+7)} =\frac{12d^2-588-12d^2-14d}{(d-7)^2*(d+7)}=\frac{-14d-588}{(d-7)^2*(d+7)}=\frac{-14*(d+42) }{(d-7)^2*(d+7)} .$4.

$\frac{5u-5v+bu-bv}{u^2-v^2}=\frac{5*(u-v)+b*(u-v)}{y^2-v^2}=\frac{(u-v)*(5+b)}{(u-v)*(u+v)} =\frac{b+5}{u+v}=\frac{-6+5}{2,6+(-3,1)}=\frac{-1}{-0,5} =2.$