Question

Ровязати систему
x^2+2y=5
3x^2+3y=39

Answer 1

$\displaystyle\left \{ {{x^{2}+2 y=5} \atop {3x^{2}+3y=39 } \ |:3} \right.\\\\\\-\displaystyle\left \{ {{x^{2}+2 y=5} \atop {x^{2}+y=13 } \right.\\--------\\y=-8\\\\x^{2}=13-(-8)=13+8=21\\\\x_{1} =\sqrt{21} \ ; \ x_{2}=-\sqrt{21}\\\\Otvet:\boxed{(\sqrt{21} \ ; \ -8) \ ; \ (-\sqrt{21} \ ; \ -8)} }$