Question

решите уравнение пожалуйста

Answer 1

$\displaystyle\left \{ {{3-2x<1} \atop {1,6+x<2,9}} \right.\\\\\\\displaystyle\left \{ {{-2x<1-3} \atop {x<2,9-1,6}} \right.\\\\\\\displaystyle\left \{ {{-2x<-2} \atop {x<1,3}} \right.\\\\\\\displaystyle\left \{ {{x>1} \atop {x<1,3}} \right.\\\\\\Otvet:\boxed{x\in(1 \ ; \ 1,3)}$