Question

сложите или вычтите алгебраические дроби​

Answer 1

$\frac{6a}{9a^{2}-1}+\frac{3a+1}{3-9a}+\frac{3a-1}{6a+2}=\frac{6a}{(3a-1)(3a+1)} +\frac{3a+1}{3(1-3a)} +\frac{3a-1}{2(3a+1)} =\frac{6a*3*2}{6(3a-1)(3a+1)} -\\\\-\frac{2(3a+1)^{2}}{6(3a-1)(3a+1)} +\frac{3(3a-1)^{2}}{6(3a-1)(3a+1)} =\frac{36a}{6(3a-1)(3a+1)} -\frac{18a^{2}+12a+2}{6(3a-1)(3a+1)} +\frac{27a^{2}-18a+3}{6(3a-1)(3a+1)} =\\\\\frac{36a-18a^{2}-12a-2+27a^{2}-18a+3}{6(3a-1)(3a+1)} =\frac{9a^{2}+6a+1}{6(3a-1)(3a+1)} =\frac{(3a+1)^{2}}{6(3a-1)(3a+1)} =\frac{3a+1}{18a-6}$