Question

ПОМОГИТЕ РЕШИТЬ СРОЧНО 5-6-7!!!

Answer 1

Ответ:

$5)\ \ \displaystyle \Big(\frac{1}{4}\Big)^{-\frac{1}{2}}\cdot 25^{\frac{1}{2}}-81^{\frac{1}{2}}\cdot 125^{-\frac{1}{3}}=4^{\frac{1}{2}}\cdot 5-9\cdot \Big(\frac{1}{5^3}\Big)^{\frac{1}{3}}=\\\\\\=2\cdot 5-9\cdot \frac{1}{5}=10-\frac{9}{5}=\frac{41}{5}=8\frac{1}{5}=8,2$

$6)\ \ \displaystyle \Big(\frac{1}{4}\Big)^{-\frac{1}{2}}\cdot 16^{\frac{1}{2}}-2^{-1}\cdot \Big(\frac{1}{25}}\Big)^{-\frac{1}{2}}\cdot 8^{-\frac{1}{3}}=4^{\frac{1}{2}}\cdot 4-\frac{1}{2}\cdot 25^{\frac{1}{2}}\cdot \Big(\frac{1}{2^3}\Big)^{\frac{1}{3}}=\\\\\\=2\cdot 4-\frac{1}{2}\cdot 5\cdot \frac{1}{2}=8-\frac{5}{4}=\frac{27}{4}=6\frac{3}{4}=6,75$

$7)\ \ \Big(\, \displaystyle \Big(\frac{1}{25}\Big)^{-\frac{1}{2}}\cdot 7^{-1}-\Big({\frac{1}{8}}\Big)^{-\frac{1}{3}}\cdot 2^{-3}\Big):49^{-\frac{1}{2}}=\Big(25^{\frac{1}{2}}\cdot \frac{1}{7}-(2^3)^{\frac{1}{3}}\cdot \frac{1}{2^3}\Big):\Big(\frac{1}{7^2}\Big)^{\frac{1}{2}}=\\\\\\=\Big(5\cdot \frac{1}{7}-2\cdot \frac{1}{8}\Big):\frac{1}{7}=\Big(\frac{5}{7}-\frac{1}{4}\Big)\cdot 7=\frac{13}{7\cdot 4}\cdot 7=\frac{13}{4}=3\frac{1}{4}=3,25$