Предмет: Физика, автор: iermakov2207

На рисунке 1 представлена схема движения катера через реку. Под каким углом α должен держать курс катер, если угол между траекторией катера и берегом должен быть 90°. Скорость катера относительно течения υкатера = 4 м/с, а скорость течения υтечения = 2 м/с. За какое время катер преодолеет реку шириной L = 233 м.

Приложения:

murrickthevex: еРкааа

murrickthevex: ответа нет шоли

iermakov2207: нет

Ответы

Автор ответа: khasanovmaks0

Ответ:

0.6666

Объяснение:

потому что равно 0

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