Question

Помогите пж надо все номера.

Answer 1

Пошаговое объяснение:

1.

$81 = {3}^{4}$

$81 = \frac{1}{ {3}^{ - 4} } = (\frac{1}{3} ) {}^{ - 4}$

$81 = {9}^{2}$

$81 = ( \frac{1}{9} ) {}^{ - 2}$

4.

$\sqrt{52 {}^{2} - 48 {}^{2} } = \sqrt{(52 - 48)} \times (52 + 48) = \sqrt{4 \times 100} = 2 \times 10 = 20$

5.

а)

$\sqrt{48} - 13 \sqrt{ \frac{12}{25} } + \sqrt{4 \frac{8}{25} } = 4 \sqrt{3} - 13 \times \frac{ \sqrt{12} }{5} + \sqrt{ \frac{108}{25} } = 4 \sqrt{3} - 13 \times \frac{2 \sqrt{3} }{5} + \frac{ \sqrt{108}}{5} = 4 \sqrt{3} - \frac{26 \sqrt{3} }{5} + \frac{6 \sqrt{3} }{5} = 0$

б)

$( \sqrt{11 + 6 \sqrt{2} } - \sqrt{11 - 6 \sqrt{2} }) {}^{2} = ( \sqrt{(3 + \sqrt{2}) {}^{2} } - \sqrt{(3 - \sqrt{2) } } {}^{2} ) {}^{2} = (3 + \sqrt{2} - (3 - \sqrt{2} )) { }^{2} = (3 + \sqrt{2} - 3 + \sqrt{2} ) {}^{2} = (2 \sqrt{2} ) {}^{2} = 4 \times 2 = 8$