Question

Квадратный корень. 5​

Answer 1

Объяснение:

1).

$\sqrt{6} \times \sqrt{150} - \frac{ \sqrt{33}^{2} }{ \sqrt{9} } = \sqrt{6 \times 150} - \frac{33}{3} = \sqrt{900} - 11 = 30 - 11 = 19$

2).

$\sqrt{3} \times \sqrt{27} - \sqrt{28}^{2} = \sqrt{3} \times \sqrt{3 \times 9} - 28 = \sqrt{3} \times \sqrt{3} \times \sqrt{9} - 28 = 3 \times 3 - 28 = 9 - 28 = - 19$

3).

$\frac{ \sqrt{72} }{ \sqrt{2} } + \sqrt{8} \times \sqrt{18} = \sqrt{ \frac{72}{2} } + \sqrt{8 \times 18} = \sqrt{36} + \sqrt{144} = 6 + 12 = 18$