Question

ПОМОГИТЕ ПОЖАЛУЙСТА СРОЧНО​

Answer 1

Ответ:

Объяснение:

(49с²-9)/(49с²+42c+9)=(7c-3)(7c+3)/(7c+3)²=(7c-3)/(7c+3)

c=-4

(7c-3)/(7c+3)=(-28-3)/(-28+3)=-31/(-25)=1,24

Answer 2

$\dfrac{49c^{2}-9 }{49c^{2}+42c+9 }=\dfrac{(7c)^{2}-3^{2} }{(7c)^{2}+2\cdot 7c\cdot 3+3^{2}}=\dfrac{(7c+3)(7c-3)}{(7c+3)^{2} }=\boxed{\dfrac{7c-3}{7c+3}} \\\\c=-4\\\\\dfrac{7c-3}{7c+3}=\dfrac{7\cdot(-4)-3}{7\cdot(-4)+3}=\dfrac{-28-3}{-28+3}=\dfrac{-31}{-25}=\boxed{1,24}$