Question

докажите тождество
$\frac{1}{x(x - 3)} + \frac{1}{(x - 3)(x - 6)} + \frac{1}{(x - 6)(x - 9} + \frac{1}{(x - 9)(x - 12)} = \frac{4}{x(x - 12)}$
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Answer 1

1.берем 2 и 3дроби =((х-9)+ (x-3))/(x-3)(x-6)(x-9)=2(x-6)/(x-3)(x-6) (x-9)=2/(x-3)(x-9)

2. берем полученный результат + 4 дробь=((2(x-12)+(x-3))/(x-3)(x-9) (x-12)=(3(x-9)))(x-3)(x-9)(x-12)=3/(x-3)(x-12)

3. берем результат +1 дробь =((x-12)+3x)/x(x-3)(x-12)=(4(x-3))/x(x-3) (x-12)=4/x(x-12)