Question

(x-⁷)² * (x-³)-⁴
(x⁶)-¹ * (x-²)-³​

Answer 1

$\frac{( { {x}^{ - 7} })^{2} \times ( { {x}^{ - 3} })^{ - 4} }{( { {x}^{ 6} })^{ - 1} \times { ({x}^{ - 2}) }^{ - 3} } = \\ = \frac{{x}^{ - 14} \times {x}^{12} }{{x}^{ - 6} \times {x}^{6} } = \\ = \frac{ {x}^{ - 14 + 12} }{ {x}^{ - 6 + 6} } = \frac{ {x}^{ - 2} }{ {x}^{0} } = \frac{ {x}^{ - 2} }{1} = {x}^{ - 2} = \frac{1}{ {x}^{2} }$