Question

(х-4)²-28,09 = 0.

Плиз помогите
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Answer 1

Ответ:

$x_{1}==9,3;\\ x_{2}= -1,3;$

Объяснение:

$(x-4)^2-28,09=0;\\(x-4)^2=28,09\\(x-4)^2=28\frac{9}{100} ;\\(x-4)^2=\frac{2809}{100};\\x-4=\sqrt{\frac{2809}{100}} ;\\x= 4+\sqrt{\frac{2809}{100}};\\x_{1}= 4+\frac{53}{10}=4+5,3=9,3;\\ x_{2}= 4-\frac{53}{10}=4-5,3=-1,3;$