Question

Помогите мне! 25 баллов

Answer 1

$\frac{4(2a-4)^{2}}{6} :\frac{8}{3} -(a^{2}+4)=\frac{4(2a-4)^{2}}{6} *\frac{3}{8} -(a^{2}+4)=\frac{(2a-4)^{2}}{4} -(a^{2}+4)=\\\\=\frac{4a^{2}-16a+16}{4} -\frac{4a^{2}+16}{4} =\frac{4a^{2}-16a+16-4a^{2}-16}{4} =\frac{-16a}{4} =-4a$