Question

решите уравнение$\sqrt{x} =x-2$

Answer 1

$\sqrt{x} =x-2\\\\\left \{ {{(\sqrt{x})^{2}=(x-2)^{2}} \atop {x-2\geq0 }} \right.\\\\\\\left \{ {{x=x^{2}-4x+4 } \atop {x\geq 2}} \right.\\\\x^{2}-4x+4=x\\\\x^{2}-5x+4=0\\\\Teorema \ Vieta:\\\\x_{1} =4\\\\x_{2}=1<2-neyd\\\\Otvet:\boxed4$