Предмет: Геометрия, автор: tolotop191

Найдите стороны параллелограмма ABCD, если его периметр равен 48, а 3AB = 5BC

Ответы

Автор ответа: C0C04EK

3

Ответ:

AB = 35/9, BC = 7/3

Объяснение:

Пускай AB = x, тогда 5BC = 3x -> BC = 3x/5.

P = 2*(AB+BC)=48

2*(3x + 3x/5)=28

3x + 3x/5 = 14 | * 5

15x + 3x = 70

x = 70/18 = 35/9

AB = 35/9, BC = 7/3

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