Question

Помогите, решите 2,4 даю 10б

Answer 1

2)

${(x {y}^{3} )}^{7} \times {( {x}^{6} {y}^{4} )}^{3} \div ( {x}^{24} {y}^{32} ) = {x}^{1 \times 7} {y}^{3 \times 7} \times {x}^{6 \times 3} {y}^{4 \times 3} \div ( {x}^{24} {y}^{32} ) = {x}^{7} {y}^{21} \times {x}^{18} {y}^{12} \div ( {x}^{24} {y}^{32} ) = ( {x}^{7 + 18} {y}^{21 + 12} ) \div ( {x}^{24} {y}^{32} ) = ( {x}^{25} {y}^{33} ) \div ({x}^{24} {y}^{32} ) = {x}^{25 - 24} {y}^{33 - 32} = {x}^{1} {y}^{1} = xy$

4)

${x}^{5} {y}^{8} \times {(xy)}^{5} \div {( {x}^{5} {y}^{3} )}^{2} = {x}^{5} {y}^{8} \times {x}^{5} {y}^{5} \div {x}^{5 \times 2} {y}^{3 \times 2} = {x}^{5 + 5} {y}^{8 + 5} \div {x}^{10} {y}^{6} = {x}^{10} {y}^{13} \div {x}^{10} {y}^{6} = {x}^{10 - 10} {y}^{13 - 6} = {x}^{0} {y}^{7} = 1 \times {y}^{7} = {y}^{7}$