Question

метод интервалов 4х^2-Х-3 больше или равно нолю ПЖЖЖЖ

Answer 1

$4x^{2} -x-3\geq 0\\4x^{2} +3x-4x-3\geq 0\\x*(4x+3)-(4x+3)\geq 0\\(4x+3)(x-1)\geq 0\\\left \{ {{4x+3\geq 0} \atop {x-1\geq 0}} \right. \\\left \{ {{4x+3\leq 0} \atop {x-1\leq 0}} \right. \\\left \{ {{x\geq -\frac{3}{4} } \atop {x\geq 1}} \right. \\\left \{ {{x\leq -\frac{3}{4} } \atop {x\leq 1}} \right.$

x∈ ( - ∞, $-\frac{3}{4}$] ∪ [ 1, + ∞)