Question

Сократите дробь: …………

Answer 1

Ответ:

$\dfrac{\sqrt{c}-\sqrt[3]{d^2}}{\sqrt[4]{c}-\sqrt[3]{d}}=\dfrac{(\sqrt[4]{c}-\sqrt[3]{d})(\sqrt[4]{c}+\sqrt[3]{d})}{\sqrt[4]{c}-\sqrt[3]{d}}=\sqrt[4]{c}+\sqrt[3]{d}$

$\star \ \ \dfrac{\sqrt{c}-\sqrt[3]{d^2}}{\sqrt[4]{c}-\sqrt[3]{b}}=\dfrac{(\sqrt[4]{c}-\sqrt[3]{d})(\sqrt[4]{c}+\sqrt[3]{d})}{\sqrt[4]{c}-\sqrt[3]{b}}\ \ \star$