Question

на языке С++
пожалуста​

Answer 1

#include <iostream>

#include <cmath>

using namespace std;

signed main()

{

  double pr = 1, n, x;

  cin >> n >> x;

  for(int k = 1; k <= n;k++){

      pr *= (1.0+sin(k*x))/k;

  }

  cout << pr << endl;

  return 0;

}