Question

№4.9. Докажите тождество:

1)(а²) ⁴×(а³) ⁵:(а³) ⁷=а²

2)(x³) ⁶×(x²) ⁵=x²⁸​

Answer 1

Объяснение:

1).

$({a}^{2})^{4} \times ({a}^{3})^{5} \div ({a}^{3})^{7} = {a}^{2}$

${a}^{2 \times 4} \times {a}^{3 \times 5} \div {a}^{3 \times 7} = {a}^{2}$

${a}^{8} \times {a}^{15} \div {a}^{21} = {a}^{2}$

${a}^{8 + 15 - 21} = {a}^{2}$

${a}^{2} = {a}^{2}$

2).

$( {x}^{3} )^{6} \times ({x}^{2})^{5} = {x}^{28}$

${x}^{3 \times 6} \times {x}^{2 \times 5} = {x}^{28}$

${x}^{18} \times {x}^{10} = {x}^{28}$

${x}^{28} = {x}^{28}$