Question

3.5. Извлеките корень из выражения, если это возможно​

Answer 1

$\displaystyle \sqrt{122^2-22^2}=\sqrt{(122-22)(122+22)}=\sqrt{100*144}=10*12=120$

$\displaystyle \sqrt{6.8^2-3.2^2}=\sqrt{(6.8-3.2)(6.8+3.2)}=\sqrt{3.6*10}=\sqrt{36}=6$

$\displaystyle \sqrt{45.8^2-44.2^2}=\sqrt{(45.8-44.2)(45.8+44.2)}=\sqrt{1.6*90}=\\\\=\sqrt{16*9}=4*3=12$

$\displaystyle \sqrt{3.13^2-3.12^2}=\sqrt{(3.13-3.12)(3.13+3.12)}=\sqrt{0.01*6.25}=\\\\=\sqrt{\frac{1*625}{100*100}}=\frac{25}{100}=0.25$