Question

Логарифм

 y=lglnctgx

Answer 1

y'=[1/(lnctgx * ln10)] *[1/ctgx] *[-1/sin^2 x]=-1/(ln10*sinx*cosx*lnctgx)=
=преобразуем sinx*cosx=sin2x/2=
=-2/(ln10*sin2x*lnctgx)