Question

помогите пожайлуста ​

Answer 1

Ответ:

Объяснение:

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Answer 2

Ответ:

$2)\ \ \left\{\begin{array}{l}xy=10\\x-2y=1\end{array}\right\ \ \left\{\begin{array}{l}x=2y+1\\(2y+1)\, y=10\end{array}\right\ \ \left\{\begin{array}{l}x=2y+1\\2y^2+y-10=0\end{array}\right\\\\\\\left\{\begin{array}{l}x_1=-4\ ,\ x_2=5\\y_1=-2,5\ ,\ y_2=2\end{array}\right\ \ \ \ \ Otvet:\ (-4\ ;-2,5\ )\ ,\ (\ 5\ ;\ 2\ )\ .$

$3)\ \ \left\{\begin{array}{l}x-y=7\\x^2+y^2=25-2xy\end{array}\right\ \ \left\{\begin{array}{l}(x-y)^2=49\\x^2+y^2=25-2xy\end{array}\right\ \ \left\{\begin{array}{l}x^2+y^2-2xy=49\\x^2+y^2=25-2xy\end{array}\right\\\\\\\left\{\begin{array}{l}x^2+y^2=2xy+49\\2xy+49=25-2xy\end{array}\right\ \ \left\{\begin{array}{l}x-y=7\\4xy=-24\end{array}\right\ \ \left\{\begin{array}{l}x=y+7\\xy=-6\end{array}\right\ \ \left\{\begin{array}{l}x=y+7\\(y+7)\, y=-6\end{array}\right$

$\left\{\begin{array}{l}x=y+7\\y^2+7y+6=0\end{array}\right\ \ \left\{\begin{array}{l}x=y+7\\y_1=-6\ ,\ y_2=-1\end{array}\right\ \ \left\{\begin{array}{l}x_1=1\ ,\ x_2=6\\y_1=-6\ ,\ y_2=-1\end{array}\right\\\\\\Otvet:\ \ (\ 1\ ;-6\ )\ ,\ (\ 6\ ;-1\ )\ .$